Pistacchio and sex

Pistacchio likes statistics only less than being outraged at people who don’t understand them, so every time a “University of Wisconsin study reveals…” story is published, he rubs his paws.

A few days ago he read one that spoke about the comparative “promiscuity” of men and women, indicating that men had, on average, 15 sexual partners in their life, while women had 7.

The study included all countries (there are 7,500 million people in the world, of which 3,710 million are women) and limited its analysis to heterosexual relationships.

He broadened his Google search and saw that the population data was correct, but each study on the subject had different results: Men 11, women 6. Men 12, women 7. Men 7, women 4. While reading her right eye she began to blinking, an unequivocal sign of the increase in blood pressure caused only by logical fallacies or the goals that cancel Racing.

Question:

And is that Pistacchio knew PERFECTLY which gender was more “promiscuous” (defined as “with the highest average number of different sexual partners in his life”) and EXACTLY in what proportion. (always limited to heterosexual relationships)

Which of the following is correct?

Answer:

The most “promiscuous” sex will ALWAYS be the one with the fewest individuals.

Since there are slightly more men than women in the world, they have + 2% of average sexual partners in their life.

To understand that this is reality, we have to realize that it is not a biological, social or behavioral problem, but simply a mathematical one.

Let’s do a simple example where there are only 5 men and 4 women. Every time there is a new sexual encounter, a man and a woman increase their number of partners by 1. Let’s imagine a man sleeping with the 4 women. He is the most promiscuous of the entire population, as there will be 1 man with 4 partners, 4 women with only one partner, and 4 men with zero partners.

By averaging “promiscuity”, the women will have had 1 partner each. And the men: One will have had 4, and four will have had 0. Therefore if we make 4 (total pairs of men) divided 5 (number of men), the average will be 0.8, which is less than 1.

You can keep trying examples and you will ALWAYS see that women will have had 25% more sexual partners than men.

Another logical exercise that helps to understand the problem is to think of it in an opposite and extreme reality.
Let’s imagine that there are 100 women in the mythological village of the Amazons and only one man arrives.

If he marries and sleeps with only one woman, “the men in the village” will have had 1 partner on average. However, only one of the 100 women will have had a partner, so the “average number of female sexual partners” is 0.01.

If he goes to bed with 100, he will have been infinitely promiscuous, with a number of 100, while each of the women (and therefore the average) will have done it with 1.

In both examples (and in any other), the man from the Amazon village was always 100 times more promiscuous than the women.

Ultimately, “promiscuity” is, strictly, the proportion that exists in a closed population, of men and women.

PS: This logic includes some simplifications, such as the lifespan of people, but none should significantly affect the result